Annulus Area
Calculator

Inputs

Area
201.061929

Results

Area
201.061929
Outer disc area
314.159265
Inner disc area
113.097335
Ring width
4

Results

Area201.061929
Outer disc area314.159265
Inner disc area113.097335
Ring width4

formula-map diagram

Area
201.061929
Outer disc area
314.159265
Inner disc area
113.097335
Ring width
4

Formula map

Formula

A = π × (R² − r²)

= 201.06192982975

Note

Simplified model: these are the exact results of the stated idealised geometric formulas, assuming perfect shapes, exact inputs and consistent units. Real measurements carry error, and results such as the cyclic-quadrilateral area only hold when the figure truly satisfies the stated condition. Verify independently before relying on these figures.

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Frequently asked questions

What is an annulus, and what is its area formula?+

An annulus is a flat ring shape, the region between two concentric circles (circles sharing the same center) of different radii. Its area is A = π(R² − r²), where R is the outer radius and r is the inner radius, simply the outer circle's area minus the inner circle's area.

Why can't I just subtract the diameters or radii directly instead of squaring them first?+

Area scales with the square of radius, not radius itself, so you must calculate each circle's full area separately (using r²) before subtracting; subtracting the radii first and then squaring would give a completely different and incorrect number. This is a very common calculation mistake with ring-shaped objects like washers or pipes.

Can this formula be simplified using the ring's width instead of both radii separately?+

Yes, since π(R²−r²) factors as π(R+r)(R−r), and if you know the ring's width w = R−r, you can rewrite the area as πw(R+r), or equivalently 2π·w·r_mean, where r_mean is the average of the two radii. This alternate form is sometimes more convenient depending on which measurements you have.

Does the annulus formula work if I only know the diameters instead of the radii?+

Yes, but you must convert diameters to radii first (dividing each by 2) before applying the formula, since the standard formula is defined in terms of radii, not diameters. Plugging diameters directly into π(R²−r²) without halving them first would overestimate the area by a factor of 4.

What real-world objects are shaped like an annulus, and why does this formula matter for them?+

Washers, gaskets, pipe cross-sections, and CDs/records are all annulus-shaped, and this formula directly gives the material area needed, useful for calculating material cost, weight, or flow area through a pipe. It's one of the more practically common area formulas in engineering and manufacturing contexts.